Question

dibantu dong kk, mumpung poin bnyak​

Answer 1

t prisma = 20 cm

a = 5 cm, tΔ = 12 cm

1/2 x 5 x 12 = 30 cm^2

Panjang sisi AC

AC^2 = AB^2 + BC^2

         = 12^2 + 5^2

         = 144 + 25

          = 169

AC = [tex]\sqrt{169\\[/tex] = 13

Keliling alas = Keliling segitiga

                    = AB + BC + AC

                    = 12 + 5 + 13

                    = 25

Luas permukaan prisma = 2 x luas alas + keliling alas x t prisma

                                         = 2 x 30cm^2 + 25 x 20

                                          = 60 + 500

                                          = 560 cm^2

Answer 2

[tex]t \: prisma = 20 \: cm \\ a = 5 \: cm, \: t = 12 \: cm \\ \\ La = \frac{1}{2} \times 5 \: cm \times 12 \: cm = 30 \: {cm}^{2} \\ {AC}^{2} = {AB}^{2} + {BC}^{2} \\ = {12}^{2} + {5}^{2} \\ = 144 + 25 \\ = 169 \\ AC = \sqrt{169} = 13 \\ \\ Keliling \: alas =AB + BC + AC \\ = 12 + 5 + 13 \\ = 30 \: cm \\ \\ LP \: prisma =2 \times La + K \: alas \times tp \\ = 2 \times 30 \: {cm}^{2} + 30 \: cm \times 20 \: cm \\ = 60 \: {cm}^{2} + 600 \: {cm}^{2} \\ = 660 \: {cm}^{2} \\ \\ Jadi \: LP \: prisma \: adalah \: 660 \: {cm}^{2} [/tex]