Question

Diameter alas suatu kerucut 10 cm jika panjang garis pelukisnya 13 cm dengan nilai phi tiga koma empat belas hitunglah tinggi kerucut volume kerucut

Answer 1

T = √s²-r²
t = √13²-5²
t = √169-25
t = √144
t = 12 cm

v = 1/3 πr²t
= 1/3 x 3,14 x 5² x 12
= 4 x 3,14 x 25
= 100 x 3,14
= 314 cm²

Answer 2

t = √s²-r²
  = √13²-5²
  = √169-25
 = √144
 = 12 cm

volum = 1/3 πr²t
         = 1/3 x 3,14 x 5² x 12
         = 4 x 3,14 x 25
         = 100 x 3,14
         = 314 cm²