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[2 3] 10 - 9 = 1
[3 5]
C invers = 1/1[5 -3]
[-3 2]
C invers adalah [5 -3]
[-3 2]
C⁻¹ = 1/det C [5 ₋3]
[₋3 2]
C⁻¹ = 1/(10 - 9) [5 ₋3]
[₋3 2]
C⁻¹ = [5 ₋3]
[₋3 2]