Materi : SPLDV
x = 3y + 5 ... (1)
2x + y = 3 ... (2)
Substitusi ( x => y )
2( 3y + 5 ) + y = 3
6y + 10 + y = 3
7y = 3 - 10
7y = -7
y = -1
---
x = 3y + 5
x = 3(-1) + 5
x = - 3 + 5
x = 2
HP = { 2,-1 } = { x,y }
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
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Materi : SPLDV
x = 3y + 5 ... (1)
2x + y = 3 ... (2)
Substitusi ( x => y )
2( 3y + 5 ) + y = 3
6y + 10 + y = 3
7y = 3 - 10
7y = -7
y = -1
---
x = 3y + 5
x = 3(-1) + 5
x = - 3 + 5
x = 2
---
HP = { 2,-1 } = { x,y }
---
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]