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Determine la distancia del punto A(-3;4;2) al plano: pi 1 =2x-4y+z-7=0​
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Dos planos son paralelos, cuando el producto de sus vectores normales es 0​
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El vector normal del plano P: 4 x - 5y + 12z - 10 = 0 es (4, - 5, 10)​
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El vector director de la recta: l: (x;y;z)=t(2;4;1)+(4;5;-1) , es (2;4;1)​
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El vector direccional de la ecuación de la recta: (3 - x)/2 = (2 - y)/- 1 = (1 - z)/3 es (2;-1;3)​
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