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A ( 10 m , 25⁹)
B ( 20 m , 140⁰)
∑Fx = 0
Ax = A cos ∅ = 10 m cos 25⁹ = 9.06 m
Bx = B cos ∅ = 20 m cos 140⁰ = - 15.32 m
∑Fx = - 6.32 m
ΣFy = 0
Ay = A sen ∅ = 10 m sen 25⁹ = 4.2 m
By = B sen ∅ = 20 m sen 140⁰ = 12.85 m
ΣFy = 17.05 m
R = √ (∑Fx)- + (∑Fy)² =
R = √(- 6.32 m)² + (17.05 m)² = 18.16 m
tang ∅ = ΣFy / ∑Fx = 17.05 m / - 6.32 m = - 2.69
∅ = shift tang (-2.69) = - 69.66 ⁰
∅x = 180⁰ - 69.66 ⁰ = 110.34⁰