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h(y) = z
g(3) = 8 --> g⁻¹(8) = 3
h(8) = 4
h g(3) = h {g(3)} = h (8) = 4
h(y) = z ⇔ h(8) = 4
Ditanya:
a). g⁻¹(8) = x
= 3
b). hg(3) = h(g(3))
= h(8)
= 4