Determinar el area de un cilindro cuyo radio de la base es igual a 25 dm (decimetros) y su altura es de 120 decimetro
nivresiul
Area de una circunferencia = Area de la base = π . (r)², r = radio El cilindro tiene 2 bases = 2 x (π x r²) =2π r² = 2(3.14) (25 dm)² = 3925 dm² Area lateral = 2π. r(h)= 2π .r .h = 2(3.14)(25 dm) (120 dm) = 18840 dm² Area total = area lateral + area de las bases = 2π . r . h + 2π . r² = 2 (3.14)(120 dm) (25 dm) + 2(3.14) (25 dm)² = 18840 dm² + 3925 dm² = 22765 dm² suerte
El cilindro tiene 2 bases = 2 x (π x r²) =2π r² = 2(3.14) (25 dm)² = 3925 dm²
Area lateral = 2π. r(h)= 2π .r .h = 2(3.14)(25 dm) (120 dm) = 18840 dm²
Area total = area lateral + area de las bases
= 2π . r . h + 2π . r²
= 2 (3.14)(120 dm) (25 dm) + 2(3.14) (25 dm)²
= 18840 dm² + 3925 dm²
= 22765 dm²
suerte