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-3,5mol de H2SO4------- x g
en estos ejercicios solo usa la regla de tres para la a,b,c,d
mol = masa/Mm
MASA= mol x Mm
masa = 3.5 mol x 98 g/mol = 343 g de H2SO4
b) Mm CaCO3 = 100 g/mol
masa = 7,0 mol x 100 g/mol = 700 g de CaCO3
c ) Mm Ca(OH)2 = 74 g/mol
masa = 4.2 mol x 74 g/mol = 310.8 g de Ca(OH)2
d ) Mm AgNO3 = 169,87 g / mol
mol = masa / Mm
mol = 255 g / 169.87 g/mol
mol = 1.501 de AgNO3