Question

determina la temperatura final de 40g de agua inicialmente a 10 °C si absorbe 1200 cal.
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Answer 1

Verified answer

Respuesta:

datos=

m= 40g

Q= 1200 cal

ce= 1cal/ g °c

ti= 10°

tf=?

1200 cal = 1cal/ g °c . 40g

ΔT = 1200 cal / (1cal/ g °c ) . (40g)

ΔT= 35°c

Tf = ΔT + Ti

Tf = 35°c + 10°c

Tf = 45°c