Respuesta:
[tex]f'(x) = - 1[/tex]
Explicación paso a paso:
[tex]\frac{d}{dx}(2x - 3x + 7) = (\frac{d}{dx}2x) - (\frac{d}{dx}3x) + (\frac{d}{dx}7) = 2(\frac{d}{dx}x) - 3(\frac{d}{dx}x) + (\frac{d}{dx}7) = 2(1) - 3(1) + (0) = 2 - 3 = - 1[/tex]
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Respuesta:
[tex]f'(x) = - 1[/tex]
Explicación paso a paso:
[tex]\frac{d}{dx}(2x - 3x + 7) = (\frac{d}{dx}2x) - (\frac{d}{dx}3x) + (\frac{d}{dx}7) = 2(\frac{d}{dx}x) - 3(\frac{d}{dx}x) + (\frac{d}{dx}7) = 2(1) - 3(1) + (0) = 2 - 3 = - 1[/tex]