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c.a=15/2=7.5
α=32
tang α=c.o/c.a despejmos c.o
tng α x c.a=c.o
tang(32)x7.5=c.o
4.68=c.o
hipotenusa²=c.o²+c.a²
h=√c.o²+c.a²
h=√4.68²+7.5
h=√12.18
h=3.49 cm
perimetro =la suma de todos su lados
p=15+3.49+3.49
p=21 cm
area de tringulo =base x altura/2
base=15 altura=c.o=4.68
A=15x4.68/2
A=35.14 cm²