Respuesta:
Explicación paso a paso:
Solución:
Radio del círculo: [tex]r = 8cm[/tex]
Lado del cuadrado: [tex]L = 2r[/tex]
[tex]L = 2 ( 8cm) = 16cm[/tex]
Area del círculo:[tex]A_{2} =?[/tex]
[tex]A_{2} =\pi r^{2}[/tex]
[tex]A_{2} = \pi (8cm)^{2} = 64\pi cm^{2} = 64(3.14) cm^{2} = 200.96cm^{2}[/tex]
Area del cuadrado: [tex]A_{1} = ?[/tex]
[tex]A_{1} = L^{2}[/tex]
[tex]A_{1} =(16cm)^{2} = 256cm^{2}[/tex]
Area sombreada:
[tex]As = A_{1} -A_{2}[/tex]
[tex]As = 256cm^{2} -200.96cm^{2}[/tex]
[tex]As = 55.04cm^{2}[/tex]
Area sombreada( As ): [tex]55.04cm^{2}[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Respuesta:
Explicación paso a paso:
Solución:
Radio del círculo: [tex]r = 8cm[/tex]
Lado del cuadrado: [tex]L = 2r[/tex]
[tex]L = 2 ( 8cm) = 16cm[/tex]
Area del círculo:[tex]A_{2} =?[/tex]
[tex]A_{2} =\pi r^{2}[/tex]
[tex]A_{2} = \pi (8cm)^{2} = 64\pi cm^{2} = 64(3.14) cm^{2} = 200.96cm^{2}[/tex]
Area del cuadrado: [tex]A_{1} = ?[/tex]
[tex]A_{1} = L^{2}[/tex]
[tex]A_{1} =(16cm)^{2} = 256cm^{2}[/tex]
Area sombreada:
[tex]As = A_{1} -A_{2}[/tex]
[tex]As = 256cm^{2} -200.96cm^{2}[/tex]
[tex]As = 55.04cm^{2}[/tex]
Respuesta:
Area sombreada( As ): [tex]55.04cm^{2}[/tex]