Respuesta:
[tex] {x}^{2} - 2x + 1 = [/tex]
[tex] {x}^{2} - 2x + 1 = 0[/tex]
[tex](x - 1)(x - 1) = 0[/tex]
[tex]x1 = 1[/tex]
[tex]x2 = 1[/tex]
Saludos
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Respuesta:
Hola.
[tex] {x}^{2} - 2x + 1 = [/tex]
[tex] {x}^{2} - 2x + 1 = 0[/tex]
[tex](x - 1)(x - 1) = 0[/tex]
[tex]x1 = 1[/tex]
[tex]x2 = 1[/tex]
Saludos