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Basándonos en el producto notable: "binomio al cuadrado", en general:
(a±b)² = a² ± 2ab + b²
Tendremos que:
a) (-x-1)² = (-x)² - 2(-x)(1) + (1)² = x² - 2x + 1
b) (2xy-a)² = (2xy)² - 2(2xy)(a)+(a)² =4x²y²-4axy+a²
c) (7x³-2y²)² = (7x³)²-2(7x³)(2y²)+(2y²)² = 49x^6-28x³y²+4y^4
Eso es todo!! Saludos! Jeizon1L