[tex](x + 3 {)}^{2} \: \: y \: \: (2x + 1 {)}^{2} = binomio \: suma \: al \: cuadrado \\ entonces \\ (x + 3 {)}^{2} \\ = {x}^{2} + 2(x)(3) + {3}^{2} \\ {x}^{2} + 6x + 9 \\ (2x + 1 {)}^{2} \\ = (2x {)}^{2} + 2(2x)(1) + {1}^{2} \\ 4 {x}^{2} + 4x + 1[/tex]
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[tex](x + 3 {)}^{2} \: \: y \: \: (2x + 1 {)}^{2} = binomio \: suma \: al \: cuadrado \\ entonces \\ (x + 3 {)}^{2} \\ = {x}^{2} + 2(x)(3) + {3}^{2} \\ {x}^{2} + 6x + 9 \\ (2x + 1 {)}^{2} \\ = (2x {)}^{2} + 2(2x)(1) + {1}^{2} \\ 4 {x}^{2} + 4x + 1[/tex]