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α = 0,000025/°C
Δt = t₁ - to
= 80 - 30
= 50°C
Ditanyakan : L₁ (Lo + ΔL)
Penyelesaian : ΔL = Lo × α × Δt
= 100 × 0,000025 × 50
= 0,125 cm
L₁ = Lo + ΔL
= 100 + 0,125
= 100,125 cm
α = 0,000025°C
Δt= 50°C
Ditanya =L. ...?
Jawab = L = 100 ( 1 + 0,000025 x 50)
100 (1 + 0,00125)
100 + 0,125
= 100,125 cm
please jadikan jawaban terbaik y...