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detaT=150-27=123'C
423,k=150'C
alfha=1,8*10pngkt-5
At=?
betha=2*alfaha
=2*1,8*10pngkt-5
=3,6*pngkt-5
At=Ao(1+betha*deltaT)
=1(1+0,000036*150)
=1(1+0,0054)
=1(1,0054)
=1,0054 m persegi