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Δx1=40 cm
Δx2=60 cm
dit:Ep pegas=?
jwb:
cari konstanta pegas dahulu
F=k.Δx1
40=0,4k
k=40/0,4
k=100 N/m
barus cari Ep
Ep=1/2 k.Δx2²
Ep=1/2.100.0,36
Ep=50.0,36
Ep=18