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Mm Al2O3 = 101.96 g/mol H2O = 18.01 g/mol Al(OH)3 = 78 .00 g/mol
Al2O3 + 3 H2O → 2 Al(OH)3
102 g + 3 ( 18 g) → 2 (78 g) 102 g + 54 g = 156 g 156 g = 156 g
SE cumple la Ley de la conssrvacion de la Masa