Deducir las formulas empiricas de las sustancias que tienen la siguiente composición en porcentaje:a. Fe=63,53%, S=36,47%; b. Fe=46,55%, S=53,45%; c. Fe=53,73%, S=46,27%
blancasalas
A. Fe = 63,53% / 56 = 1,13/1,13= 1 S = 36,47% / 32 = 1,14/1,13 = 1 FORMULA = FeS
b. Fe = 46,55% / 56 = 0,83 /0,83 = 1 S = 53,45% / 32 = 1,7 /0,83 = 2 FORMULA = FeS₂
c. Fe = 53,73% /56 = 0,96 /0,96 = 1 S =46,27% /32 = 1,45/0,96 = 1,5≈2 FORMULA = FeS₂
FORMULA = FeS
b. Fe = 46,55% / 56 = 0,83 /0,83 = 1 S = 53,45% / 32 = 1,7 /0,83 = 2
FORMULA = FeS₂
c. Fe = 53,73% /56 = 0,96 /0,96 = 1 S =46,27% /32 = 1,45/0,96 = 1,5≈2
FORMULA = FeS₂