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u2= a r
u3= a r^2
a - a.r + a.r^2=9
a x a.r x a.r^2 = 216 = a^3r^3 = 216 diakar 3 = ar=6
a - 6 + ar^2 = 9
a + ar^2 = 15
a(1 + r^2) = 15
a = 15/(1 + r^2)
(1+r^2)(1+r^2)=15
r^2=14
a(1+14)=15
a+14a= 15
a=1
U3= ar^2 = 1 x 14 = 14