Odpowiedź:
[tex]a_n=2n-3\\a_1=2\cdot1-3=-1\\a_{n+1}=2\cdot(n+1)-3=2n+2-3=(2n-3)+2=a_n+2\\\left\{\begin{array}{llc}a_1=-1\\a_{n+1}=a_n+2\end{array}\right[/tex]
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Odpowiedź:
[tex]a_n=2n-3\\a_1=2\cdot1-3=-1\\a_{n+1}=2\cdot(n+1)-3=2n+2-3=(2n-3)+2=a_n+2\\\left\{\begin{array}{llc}a_1=-1\\a_{n+1}=a_n+2\end{array}\right[/tex]