Odpowiedź:
[tex]A\\\sqrt{3}+\sqrt{27}-\sqrt{6} = \sqrt{3}+3\sqrt{3}-\sqrt{6}=4\sqrt{3}-\sqrt{6}\\B\\\sqrt{3}+\sqrt{27}-\sqrt{12} =\sqrt{3}+3\sqrt{3}-2\sqrt{3}=2\sqrt{3}\\C\\\sqrt{27}-\sqrt{6}-\sqrt{12}=3\sqrt{3}-\sqrt{6}-2\sqrt{3}=\sqrt{3}-\sqrt{6}\\ D\\ \sqrt{3} -\sqrt{6} -\sqrt{12} =\sqrt{3}-\sqrt{6} -2\sqrt{3}=-\sqrt{3}-\sqrt{6} \\[/tex]
Odp: B
Szczegółowe wyjaśnienie:
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Odpowiedź:
[tex]A\\\sqrt{3}+\sqrt{27}-\sqrt{6} = \sqrt{3}+3\sqrt{3}-\sqrt{6}=4\sqrt{3}-\sqrt{6}\\B\\\sqrt{3}+\sqrt{27}-\sqrt{12} =\sqrt{3}+3\sqrt{3}-2\sqrt{3}=2\sqrt{3}\\C\\\sqrt{27}-\sqrt{6}-\sqrt{12}=3\sqrt{3}-\sqrt{6}-2\sqrt{3}=\sqrt{3}-\sqrt{6}\\ D\\ \sqrt{3} -\sqrt{6} -\sqrt{12} =\sqrt{3}-\sqrt{6} -2\sqrt{3}=-\sqrt{3}-\sqrt{6} \\[/tex]
Odp: B
Szczegółowe wyjaśnienie: