Odpowiedź:
[tex]log_618=\frac{1+2a}{1+a}[/tex]
Szczegółowe wyjaśnienie:
[tex]a=log_23[/tex]
[tex]log_618=log_6(6\cdot3)=lpg_66+log_63=1+log_63=1+\frac{log_23}{log_26}=1+\frac{log_23}{log_2(2\cdot3)}=[/tex]
[tex]1+\frac{log_23}{log_22+log_23}=1+\frac{a}{1+a}=\frac{1+a}{1+a}+\frac{a}{1+a}=\frac{1+a+a}{1+a}=\frac{1+2a}{1+a}[/tex]
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Odpowiedź:
[tex]log_618=\frac{1+2a}{1+a}[/tex]
Szczegółowe wyjaśnienie:
[tex]a=log_23[/tex]
[tex]log_618=log_6(6\cdot3)=lpg_66+log_63=1+log_63=1+\frac{log_23}{log_26}=1+\frac{log_23}{log_2(2\cdot3)}=[/tex]
[tex]1+\frac{log_23}{log_22+log_23}=1+\frac{a}{1+a}=\frac{1+a}{1+a}+\frac{a}{1+a}=\frac{1+a+a}{1+a}=\frac{1+2a}{1+a}[/tex]