Odpowiedź:
f ( x) = ( [tex]2\sqrt{2} )^x[/tex]
więc
f ( 2[tex]\sqrt{2} ) = (2\sqrt{2} )^{2\sqrt{2} } = [ ( 2\sqrt{2} )^2]^{\sqrt{2} } = 8^{\sqrt{2} }= (2^3)^{\sqrt{2}}[/tex] [tex]= 2^{3\sqrt{2} } > 2^4 = 16[/tex]
Szczegółowe wyjaśnienie:
3[tex]\sqrt{2}[/tex] ≈ 3*1,41 ≈ 4,23 > 4
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Odpowiedź:
f ( x) = ( [tex]2\sqrt{2} )^x[/tex]
więc
f ( 2[tex]\sqrt{2} ) = (2\sqrt{2} )^{2\sqrt{2} } = [ ( 2\sqrt{2} )^2]^{\sqrt{2} } = 8^{\sqrt{2} }= (2^3)^{\sqrt{2}}[/tex] [tex]= 2^{3\sqrt{2} } > 2^4 = 16[/tex]
Szczegółowe wyjaśnienie:
3[tex]\sqrt{2}[/tex] ≈ 3*1,41 ≈ 4,23 > 4