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2x + 5y = 4
x + 2y = 1
x = 1 - 2y
substitusi
2x + 5y = 4
2 (1 - 2y) + 5y = 4
2 - 4y + 5y = 4
y = 4 - 2
y = 2
x = 1 - 2y
x = 1 - 2(2)
x = 1 - 4
x = -3
x + y = (-3) + 2 = -1
2x + 5y = 4 ⇒ dikali 1 ⇒ 2x + 5y = 4 -
- y = -2
y = 2
2x + 4y = 2
2x + 4(2) = 2
2x = 2 - 8
x = -6/2 = -3
x + y = - 3 + 2 = -1