Odpowiedź:
-2≤x≤2
[tex]\displaystyle |x+2|+|x-2|+\sqrt{x^{2} -6x+9} = |x+2|+|x-2|+\sqrt{(x-3)^2}= |x+2|+|x-2|+\\+|x-3|=x+2-(x-2)-(x-3)=x+2-x+2-x+3=-x+7[/tex]
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Verified answer
Odpowiedź:
-2≤x≤2
[tex]\displaystyle |x+2|+|x-2|+\sqrt{x^{2} -6x+9} = |x+2|+|x-2|+\sqrt{(x-3)^2}= |x+2|+|x-2|+\\+|x-3|=x+2-(x-2)-(x-3)=x+2-x+2-x+3=-x+7[/tex]