Question

Dalam 2 gram natrium hidroksida (NaOH) dilarutkan dalam 90 gr air (H2O) jika Ar H=1 Na=23 O=16. Tentukan Xterlarut dan Xpelaru

Answer 1

Mr NaOH = 40
mol NaOH = gr/Mr = 2/40 = 0,05 mol

Mr H₂O = 18
mol H₂O = gr/Mr = 90/18 = 5 mol

X terlarut


X pelarut

Answer 2

Cari mol dulu

n= m/mr
=2/40
=0,05

air
90/18
=5

xter= nter/(nter+ xpel)
=0,05/(0,05+5)
=0,0099

xpel= npel/(nter+npel)
=5/(0,05+5)
=0,99