Odpowiedź:
H₂S, H(l) S=x
(l)×2 + x=0
2+x=0
x= -2=> S(-ll)
PbO, Pb=x O(-ll)
x+(-ll)=0
x=ll=> Pg(ll)
HBr, H(l) Br=x
(l)+ x=0
x= -l=> Br(-l)
HBrO3 H(l) Br=x O(-ll)
(l)+ x+ 3×(-ll)=0
1+ x +(-6)=0
x= -1+6=5=> Br(V)
Wyjaśnienie:
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Odpowiedź:
H₂S, H(l) S=x
(l)×2 + x=0
2+x=0
x= -2=> S(-ll)
PbO, Pb=x O(-ll)
x+(-ll)=0
x=ll=> Pg(ll)
HBr, H(l) Br=x
(l)+ x=0
x= -l=> Br(-l)
HBrO3 H(l) Br=x O(-ll)
(l)+ x+ 3×(-ll)=0
1+ x +(-6)=0
x= -1+6=5=> Br(V)
Wyjaśnienie: