Odpowiedź:
[tex]a)[/tex] [tex]\frac{2-4x}{2} > -1[/tex]
[tex]2-4x > -2[/tex]
[tex]-4x > -4[/tex]
[tex]x < 1[/tex]
[tex]b) \frac{3x-1}{-1}\geq -3[/tex]
[tex]1-3x\geq -3\\-3x\geq -4\\x\leq \frac{4}{3}[/tex]
[tex]c)\frac{3x+6}{3} < \frac{x}{3} \\3x+6 < x\\2x < -6\\x < -3[/tex]
[tex]d)\frac{-2x+9}{0,5} \leq \frac{-x}{0,1} \\{2(-2x+9)}\leq -10x\\-4x+18\leq -10x\\18\leq -6x\\x\leq -3[/tex]
Szczegółowe wyjaśnienie:
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Odpowiedź:
[tex]a)[/tex] [tex]\frac{2-4x}{2} > -1[/tex]
[tex]2-4x > -2[/tex]
[tex]-4x > -4[/tex]
[tex]x < 1[/tex]
[tex]b) \frac{3x-1}{-1}\geq -3[/tex]
[tex]1-3x\geq -3\\-3x\geq -4\\x\leq \frac{4}{3}[/tex]
[tex]c)\frac{3x+6}{3} < \frac{x}{3} \\3x+6 < x\\2x < -6\\x < -3[/tex]
[tex]d)\frac{-2x+9}{0,5} \leq \frac{-x}{0,1} \\{2(-2x+9)}\leq -10x\\-4x+18\leq -10x\\18\leq -6x\\x\leq -3[/tex]
Szczegółowe wyjaśnienie: