Odpowiedź:
tgα= √5
tg²α = (√5)² = 5
sin²α/cos²α = 3
sin²α = 5cos²α
1 - cos²α = 5cos²α
- cos²α - 5cos²α = - 1 | * (- 1)
cos²α + 5cos²α = 1
6cos²α = 1
cos²α = 1/6
Odp: A
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Odpowiedź:
tgα= √5
tg²α = (√5)² = 5
sin²α/cos²α = 3
sin²α = 5cos²α
1 - cos²α = 5cos²α
- cos²α - 5cos²α = - 1 | * (- 1)
cos²α + 5cos²α = 1
6cos²α = 1
cos²α = 1/6
Odp: A