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{x l -2 < x < 3, x ∈ Range} >> R = range
penyelesaian :
1. f(x) = -1
f(x) = 2x - 1
f(-1) = 2(-1) - 1
= -2 - 1
= -3
2. f(x) = 0
f(x) = 2x -1
f(0) = 2(0) - 1
= 0 - 1
= -1
3. f(x) = 1
f(x) = 2x - 1
f(1) = 2(1) - 1
= 2 - 1
= 1
4. f(x) = 2
f(x) = 2x - 1
f(2) = 2(2) - 1
= 4 - 1
= 3
Range (daerah hasil) = {-3, -1, 1, 3}
semoga membantu...:)