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1) X || AC → X = kAC = (-k,5k)
||X|| = k ||AC|| = k √26 = 10 → k = 10 / √26
X = (-10 / √26 ; 50 / √26)
ó
X = (10 / √26 ; -50 / √26)
2) X ⊥ CA → X·CA = 0
X=(a,b) → (a,b)·(-1,5) = 0
-a + 5b = 0 → a = 5b
||X||² = 100 → a² + b² = 100
(5b)² + b² = 100
|b| = 10 / √26 → |a| = 50 / √26
X= (50 / √26, 10 / √26) ó X= (-50 / √26, -10 / √26)