Respuesta:
[tex]área \: total =2 \pi {r}^{2} + 2\pi.rg \\ = 2\pi(4)^{2} + 2\pi(4)(10) \\ = 112\pi {cm}^{2} [/tex]
[tex]volúmen = \pi {r}^{2} g \\ = \pi(4) {}^{2} (10) \\ = 160\pi {cm}^{3} [/tex]
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Respuesta:
[tex]área \: total =2 \pi {r}^{2} + 2\pi.rg \\ = 2\pi(4)^{2} + 2\pi(4)(10) \\ = 112\pi {cm}^{2} [/tex]
[tex]volúmen = \pi {r}^{2} g \\ = \pi(4) {}^{2} (10) \\ = 160\pi {cm}^{3} [/tex]