Dada la expresión L = 2π^2h si r se incrementa en un 20℅y h se disminuye en un 10℅ entonces la variación porcentual de La es
A 8%
B16, 4℅
C 29,6℅
D 54,3 ℅
A 8%
B16, 4℅
C 29,6℅
D 54,3 ℅
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Respuesta:
L= 2R².H .......................................(1)
L= 2(R +20%R)².(H -10%H) ........................(2)
L= 2(120%R)²(90%H)
L= 2(1.2R)²(0.9H)
L= 2(1.44R²)(0.9H)
L= 2.592R².H
2R².H ----------------- 100%
2.592R².H ------------- x
x= (100)×(2.592R².H )÷(2R².H )
X=(259.2)÷2
X= 129.6%
ahora la variación es 129.6% - 100%= 29.6%
Explicación paso a paso: