dla b:
[tex]c = \frac{Q}{m*dT} = \frac{100J}{0.2kg*2st} = 250 \frac{J}{kg*K}[/tex]
takie ciepło właściwe ma ołów
dla a:
[tex]c = \frac{Q}{m*dT} = \frac{100J}{0.2kg*4st} = 125\frac{J}{kg*K}[/tex]
takie CW ma srebro
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dla b:
[tex]c = \frac{Q}{m*dT} = \frac{100J}{0.2kg*2st} = 250 \frac{J}{kg*K}[/tex]
takie ciepło właściwe ma ołów
dla a:
[tex]c = \frac{Q}{m*dT} = \frac{100J}{0.2kg*4st} = 125\frac{J}{kg*K}[/tex]
takie CW ma srebro