Question

czy ktoś moze juz robił cos takiego.Zadanie w załączniku.​

Answer 1

Verified answer

Odpowiedź:

[tex]\sqrt{150} = \sqrt{25*6} =\sqrt{25} *\sqrt{6} = 5\sqrt{6}[/tex]

[tex]\sqrt{32} = \sqrt{16*2} = 4\sqrt{2}[/tex]

[tex]\sqrt{75} = \sqrt{25*3} = 5\sqrt{3}[/tex]

[tex]\sqrt{120} = \sqrt{4*30} = 2\sqrt{30}[/tex]

[tex]\sqrt{250} = \sqrt{25*10} = 4\sqrt{10}[/tex]

[tex]\sqrt{18} = \sqrt{9*2} = 3\sqrt{2}[/tex]

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[tex]\frac{10}{\sqrt{5} } *\frac{\sqrt{5} }{\sqrt{5} } = \frac{10\sqrt{5} }{5} = 2\sqrt{5}[/tex]

[tex]\frac{6}{2\sqrt{3} } = \frac{3}{\sqrt{3} } = \sqrt{3}[/tex]

[tex]\frac{5\sqrt{2} }{\sqrt{10} } *\frac{\sqrt{10} }{\sqrt{10} } =\frac{5\sqrt{20} }{10} =\frac{\sqrt{4*5} }{2} = \frac{2\sqrt{5} }{2} = \sqrt{5}[/tex]

[tex]\frac{\sqrt{6}- 2 }{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} } = \frac{\sqrt{18} -2\sqrt{3} }{3} = \frac{3\sqrt{2} - 2\sqrt{3} }{3}[/tex]

[tex]\frac{2 - \sqrt{10} }{2\sqrt{5} } *\frac{\sqrt{5} }{\sqrt{5} } = \frac{2\sqrt{5} -\sqrt{25*2} }{2*5}= \frac{2\sqrt{5} - 5\sqrt{2} }{10}[/tex]

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Szczegółowe wyjaśnienie:

[tex]\sqrt{a*b} = \sqrt{a} *\sqrt{b}[/tex]