Czy 50 g 10% kwasu solnego roztworzy 1,6 g tlenku zelaza (III)
Czy 50 g 10% kwasu solnego roztworzy 1,6 g tlenku zelaza (III)
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Cp=10%
mr=50g
ms=Cp*mr/100%
ms=10*50/100
ms=5g HCl
mHCl=36,5u
mFe2O3=160u
Fe2O3 + 6HCl---->2FeCl3 + 3H2O
160g Fe2O3------219g HCl
1,6g Fe2O3---------xg HCl
x = 2,19g HCl
TAK, roztworzy