1 mol 2 mol
H2+I2--->2 HI
x mol 0,3 mol
1 mol---2 mol
x mol---0,3 mol
x=0,15 mol
Odp: Tak, wystarczy
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1 mol 2 mol
H2+I2--->2 HI
x mol 0,3 mol
1 mol---2 mol
x mol---0,3 mol
x=0,15 mol
Odp: Tak, wystarczy