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ab=2x y cd=x y bc=z
•ab + 2ac + 3ad = bd-3bc + 42,
reemplazamos
•2x+2(2x+z)+3(2x+x+z)=z+x-3z+42
•2 x + 4x + 2 Z + 9 x + 3 Z= x - 2z +42
• 15 x + 5z= x - 2z + 42
•14 x + 7 Z = 42
•7(2x+z) =42
• 2x+z=6
•ac=6