" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
En función de sus factores primos
60/2
30/2
15/3 60 = 2^2x3x5
5/5 numero divisores = (2 + 1)(1 + 1)(1 + 1) = 12
1 D(60) = {1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60}
Tomando los divisores de 2 a 2, son 6 los rectángulos
con área de 60 m^2
1 x 60
2 x 30
3 x 20
4 x 15
5 x 12
6 x 10
EXISTEN 6 RECTÁNGULOS