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(X/3) = Un tercio de los libros
(X/4) = Un cuarto de los libros
(X/2) = Mitad de los libros
Condicion:
(X/4) + (X/3) = 10 + X/2
(X/4) + (X/3) = [3X + 4X]/12 = 7X/12
7X/12 = 10 + X/2
7X/12 - X/2 = 10
7X/12 - X/2 = [7X - 6(X)]/12 = [7X - 6X]/12 = X/12
X/12 = 10
X = (12)(10)
X = 120 Libros
Probemos:
120/4 = 30
120/3 = 40
120/2 = 60
30 + 40 = 60 + 10
70 = 70
Cumple
Rta: Hay 120 Libros