Question

Cuantos atomos de hierro estan presentes en 22,21 gramos de hierro

Answer 1

Mm Fe = 55,85 g/mol

1. calcular moles n = m/Mm

n = 22.21 g/ 55.85 g/mol

n = 0.398 moles

2. calcular átomos

1 mol ----- 6.022 x 10²³ átomos

0.398 mol ------ x

x = 2.396 x 10²³ çatomos de hierro

Answer 2

Pat (Fe) = 55.85g/mol

22.21g × ( 1 mol / 55.85 g ) × (6.022×10^23 átomos / 1 mol)

= 2.4×10^23 átomos de Hierro