Respuesta:
El diagonal menor del rombo mide 8 m
Explicación paso a paso:
Área del rombo = [tex]\frac{diagonal menor.diagonal mayor}{2}[/tex]
80 x 2 = diagonal menor x 20
160 = diagonal menor x 20
160 ÷ 20 = diagonal menor
8 = diagonal menor
Comprobamos:
80[tex]m^{2}[/tex] = [tex]\frac{diagonal menor.diagonal mayor}{2}[/tex]
80[tex]m^{2}[/tex] = [tex]\frac{8.20}{2}[/tex]
80[tex]m^{2}[/tex] = 160 ÷ 2
80[tex]m^{2}[/tex] = 80[tex]m^{2}[/tex]
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Respuesta:
El diagonal menor del rombo mide 8 m
Explicación paso a paso:
Área del rombo = [tex]\frac{diagonal menor.diagonal mayor}{2}[/tex]
80 x 2 = diagonal menor x 20
160 = diagonal menor x 20
160 ÷ 20 = diagonal menor
8 = diagonal menor
Comprobamos:
80[tex]m^{2}[/tex] = [tex]\frac{diagonal menor.diagonal mayor}{2}[/tex]
80[tex]m^{2}[/tex] = [tex]\frac{8.20}{2}[/tex]
80[tex]m^{2}[/tex] = 160 ÷ 2
80[tex]m^{2}[/tex] = 80[tex]m^{2}[/tex]