espero que te ayude .....
Respuesta:
x₁ = -(2/3), x₂= -1
Explicación paso a paso:
[tex]Ec.cuadr\'atica\\Ax^{2} +Bx+C=0\\Resoluci\'on:\\[/tex]
[tex]x= \frac{-B\left \ {{+} \atop {-}} \right. \sqrt{B^{2} -4AC} }{2A}\\x= \frac{-5\left \ {{+} \atop {-}} \right. \sqrt{5^{2} -4(3)(2)} }{2(3)}\\x= \frac{-5\left \ {{+} \atop {-}} \right. \sqrt{1} }{6}\\x= \frac{-5\left \ {{+} \atop {-}} \right. 1 }{6}\\\\x_{1} = \frac{-4}{6} =\frac{-2}{3} \\x_{2} = \frac{-6}{6} = -1[/tex]
Espero te haya sido de ayudaSaludos.
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espero que te ayude .....
Respuesta:
x₁ = -(2/3), x₂= -1
Explicación paso a paso:
[tex]Ec.cuadr\'atica\\Ax^{2} +Bx+C=0\\Resoluci\'on:\\[/tex]
[tex]x= \frac{-B\left \ {{+} \atop {-}} \right. \sqrt{B^{2} -4AC} }{2A}\\x= \frac{-5\left \ {{+} \atop {-}} \right. \sqrt{5^{2} -4(3)(2)} }{2(3)}\\x= \frac{-5\left \ {{+} \atop {-}} \right. \sqrt{1} }{6}\\x= \frac{-5\left \ {{+} \atop {-}} \right. 1 }{6}\\\\x_{1} = \frac{-4}{6} =\frac{-2}{3} \\x_{2} = \frac{-6}{6} = -1[/tex]
Espero te haya sido de ayuda
Saludos.