Respuesta:
45 mol [tex]O_{2}[/tex]
Explicación:
(Balancear)
[tex]C_{3}H_{8}+O_{2}[/tex] → [tex]CO_{2} +H_{2}O[/tex]
[tex]1C_{3} H_{8} +5O_{2}[/tex] → [tex]3CO_{2} +4H_{2}O[/tex]
(Ecuación)
1 mol [tex]C_{3} H_{8}[/tex] = 5 mol [tex]O_{2}[/tex]
7 mol [tex]C_{3} H_{8}[/tex] = X mol [tex]O_{2}[/tex]
X = 7(5)
X = 45 mol [tex]O_{2}[/tex]
Espero te ayude ;)
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Respuesta:
45 mol [tex]O_{2}[/tex]
Explicación:
(Balancear)
[tex]C_{3}H_{8}+O_{2}[/tex] → [tex]CO_{2} +H_{2}O[/tex]
[tex]1C_{3} H_{8} +5O_{2}[/tex] → [tex]3CO_{2} +4H_{2}O[/tex]
(Ecuación)
1 mol [tex]C_{3} H_{8}[/tex] = 5 mol [tex]O_{2}[/tex]
7 mol [tex]C_{3} H_{8}[/tex] = X mol [tex]O_{2}[/tex]
X = 7(5)
X = 45 mol [tex]O_{2}[/tex]
Espero te ayude ;)