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Hay 8 g de NaOH
Na=22.98g
O=16g
H=1g
16+1+22.98≈ 40g
La carga del cation es Na+ entonces
40/1=40g
8g÷40g/mol = 0.2 mol
0.2 mol = 200 ml
X = 1000ml
Respuesta. 1N