Explicación:
Por ley de Graham:
[tex]\frac{vH2}{vHe} = \sqrt{\frac{PMHe}{PMH2} }\\\\\frac{vH2}{vHe} = \sqrt{\frac{4}{2} } \\\\\frac{vH2}{vHe} = \sqrt2\\\\vH2} = (\sqrt2)vHe[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Explicación:
Por ley de Graham:
[tex]\frac{vH2}{vHe} = \sqrt{\frac{PMHe}{PMH2} }\\\\\frac{vH2}{vHe} = \sqrt{\frac{4}{2} } \\\\\frac{vH2}{vHe} = \sqrt2\\\\vH2} = (\sqrt2)vHe[/tex]