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Saquemos los moles de cloruro de sodio (NaCL)
Na=22.98 g/mol
Cl=35.45/mol
35.45+22.98=58.43 g/mol
Hay 348g de NaCl
348g÷58.43g/mol = 5.95 mol
Hacemos la division
5.95 mol ÷ 2L = 2.975 mol/L